-16x^2+96x+1152=0

Solution for -16x^2+96x+1152=0 equation:

-16x^2+96x+1152=0

a = -16; b = 96; c = +1152;
Δ = b2-4ac
Δ = 962-4·(-16)·1152
Δ = 82944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{82944}=288$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-288}{2*-16}=\frac{-384}{-32}
=+12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+288}{2*-16}=\frac{192}{-32}
=-6
$